# electrochemistry previous year questions

Answer: Ag + + e – ——> Ag(s) 1 Faraday of … (4) X = Fe, Y = Zn (1)Zn         (2) Pb         (3) Cr        (4) Cu. The Gibbs energy for the decomposition of $\mathrm{Al}_{2} \mathrm{O}_{3}$ at $500^{\circ} \mathrm{C}$ is as follows : (3) $\lambda_{\mathrm{C}}=\lambda_{\infty}+(\mathrm{B}) \mathrm{C}$ (4) $\lambda_{\mathrm{C}}=\lambda_{\infty}-(\mathrm{B}) \mathrm{C}$ Register online for Chemistry tuition on Vedantu.com to score more marks in CBSE board examination. info@entrancei.com 5. (2) 3.2 hours Scroll below to select your subject or search year wise question papers. an electrolyte. Solving the last years' question papers can help you understand the difficulty level of the paper, type of questions asked in the exam, analyze your performance, etc. The branch of chemistry that deals with the chemical changes produced by electric current and the electricity generation by chemical changes is known as electrochemistry. In a hydrogen-oxygen fuel cell, combustion of hydrogen occurs to, (b) create a potential difference between the two electrodes. Plus Two Chemistry Chapter Wise Previous Year Question Paper - Kerala Board Previous Year Question Paper Class 12 Chemistry with Solutions are now available for download in PDF format. $966 \times 10^{3}=4 \times 96500 \times \mathrm{E} \Rightarrow \mathrm{E}=2.5 \mathrm{V}$, $\frac{2}{3} \mathrm{Al}_{2} \mathrm{O}_{3} \longrightarrow \frac{4}{3} \mathrm{Al}+\mathrm{O}_{2}, \mathrm{AG}=+966 \mathrm{KJ} \mathrm{mol}^{-1}$ The potential difference needed for electrolytic reduction of $\mathrm{Al}_{2} \mathrm{O}_{3}$ at $500^{\circ} \mathrm{C}$ is at least :-, (1) 5.0 V      (2) 4.5 V       (3) 3.0 V         (4) 2.5 V, $966 \times 10^{3}=4 \times 96500 \times \mathrm{E} \Rightarrow \mathrm{E}=2.5 \mathrm{V}$, Q. Free PDF download of Important Questions for CBSE Class 12 Chemistry Chapter 3 - Electrochemistry prepared by expert Chemistry teachers from latest edition of CBSE(NCERT) books. (1) The Gibbs energy for the decomposition of $\mathrm{Al}_{2} \mathrm{O}_{3}$ at $500^{\circ} \mathrm{C}$ is as follows : Resistance of 0.2 M solution of an electrolyte is $50 \Omega$. Introduction to galvanic/voltaic cells. NATIONAL ELIGIBILITY CUM ENTRANCE TEST(UG) – 2020 [NEET(UG)-2020] will be conducted by the Central Board of Secondary Education (CBSE), for admission to MBBS/BDS Courses in India in Medical/Dental Colleges run with the approval of Medical Council of India/Dental Council of India under the Union Ministry of Health and Family Welfare, Government of India except for the institutions … They need to choose the correct option. (2) $\mathrm{Cr}^{3+}$ Please answer this question. Free Question Bank for NEET Chemistry Electrochemistry. The maximum age limit is 30 years as on December 31, of the year of admission for students belonging to reserved category. (2) X = Ni, Y = Fe (3) $\mathrm{Mn}^{2+}$ It will help you to … JEE-Mains 2018 Class 12 Marks/Qualification Students must have passed class 12 board exam or an equivalent exam from a recognized board with at least five mandatory subjects like Physics, Chemistry, Biology, English and an elective subject. The correct relationship between $\lambda_{\mathrm{C}}$ and $\lambda_{\infty}$ is given as: At 298 K, the standard reduction potentials are 1.51 V for $\mathrm{MnO}_{4}-| \mathrm{Mn}^{2+}$ , 1.36 V for $\mathrm{Cl}_{2} | \mathrm{Cl}^{-}$, 1.07 V for $\mathrm{Br}_{2} | \mathrm{Br}^{-},$ and $0.54 \mathrm{V}$ for $\mathrm{I}_{2} | \mathrm{I}^{-} .$ At $\mathrm{pH}=3$, permanganate is expected to oxidize $\left(\frac{\mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{V}\right):-$, A variable, opposite external potential $\left(\mathrm{E}_{\mathrm{ext}}\right)$ is applied to the cell. $\mathrm{E}^{\circ}=\frac{3 \times-0.036+2 \times 0.439}{1}=0.77 \Rightarrow \mathrm{A}$. How long (approximate) should water be electrolysed by passing through 100 (1)Zn         (2) Pb         (3) Cr        (4) Cu Class 12 Chemistry Electrochemistry have different set of questions. The value of standard electrode potential for the change. There are many more useful educational material which the students can download in pdf format and use them for studies. Electrodes and voltage of Galvanic cell. of the cell is found to be 0.295 V at 25°C. It has anelectrical potential of 1.1 V. (3) $625 \times 10^{-4} \mathrm{S} \mathrm{m}^{2} \mathrm{mol}^{-1}$ Save. Resistance of 0.2 M solution of an electrolyte is $50 \Omega$. Currently only available for. 6. SHOW SOLUTION Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Fact, (1) $\lambda_{\mathrm{C}}=\lambda_{\infty}-(\mathrm{B}) \sqrt{\mathrm{C}}$, (2) $\lambda_{\mathrm{C}}=\lambda_{\infty}+(\mathrm{B}) \sqrt{\mathrm{C}}$, (3) $\lambda_{\mathrm{C}}=\lambda_{\infty}+(\mathrm{B}) \mathrm{C}$, (4) $\lambda_{\mathrm{C}}=\lambda_{\infty}-(\mathrm{B}) \mathrm{C}$, Q. (4) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}$ (1) 0.770 V (2) –0.27 V (3) –0.072 V (4) 0.385 V Two Faraday of electricity is passed through a solution of $\mathrm{CuSO}_{4}$. SHOW SOLUTION (3) $\mathrm{Br}^{-}$ and $\mathrm{I}^{-}$ Here you can get the link to Download Bharathiar University Question Papers. (1) 2g         (2) 127 g          (3) 0 g          (4) 63.5 g Previous Year Papers. Find all the NEET Chemistry important questions from the chapter Electrochemistry with solutions to perform better in the exam here. JEE Main Previous Year Papers Questions of Chemistry with Solutions are available at eSaral. (3) $\mathrm{Cr}^{3+}$ (2) anode to cathode and cathode to anode $\mathrm{Fe}^{+3}_{(\mathrm{aq})}+\mathrm{e}^{-} \longrightarrow \mathrm{Fe}^{+2}_{(\mathrm{aq})}$ will be :- SHOW SOLUTION (1)Cr JEE-Mains (online) 2015 For what concentration of Ag+ will the EMF of te given cell be zero at 25 C .If the concentration of Cu2+ is 0.1 M. EoAg+ = 0.80v and Eo Cu2+ = 0.34 V Please answer. Question 1. Practicing JEE Main chapter wise questions of Chemistry will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas. Q. Nov 24,2020 - Test: Previous Year Questions - Electrochemistry (Level 1) | 21 Questions MCQ Test has questions of Class 12 preparation. For a cell reaction involving a two-electron change, the standard e.m.f. (4) JEE-Mains (online) 2015 (a) Corrosion of iron can be minimized by forming contact with another metal with a higher reduction potential. Hence, $\mathrm{MnO}_{4}^{-}$ is stronger oxidising agent. IIT JEE. $\mathrm{Fe}^{+3}_{(\mathrm{aq})}+\mathrm{e}^{-} \longrightarrow \mathrm{Fe}^{+2}_{(\mathrm{aq})}$ will be :-, (1) 0.770 V (2) –0.27 V (3) –0.072 V (4) 0.385 V, $\mathrm{E}^{\circ}=\frac{3 \times-0.036+2 \times 0.439}{1}=0.77 \Rightarrow \mathrm{A}$, Q. Multiple Choice Questions (Type-I) Login. The unit tests, chapter wise solved papers, important questions, and questions asked in previous year exams are included in CBSE test papers and CBSE practice papers with solution and answer keys. S1: Conductivity always increases with decrease in the concentration of electrolyte. MCQs are the questions in which students of JEE can gain marks or can lose marks very easily. (1) $\mathrm{Cl}^{-}$ and $\mathrm{Br}^{-}$ (4) cathode to anode and anode to cathode (d) Iron corrodes more rapidly in saltwater because its electrochemical potential is higher. Zinc acts as a sacrificial metal. The mass of copper deposited at the cathode is : Galvanization is applying a coating of :-, How long (approximate) should water be electrolysed by passing through 100, Nuclear Chemistry – JEE Main Previous Year Questions with Solutions, JEE Main Previous Year Questions Topicwise, Atomic Structure Revision Video – Class 11, JEE, NEET, Ferromagnetic Substance – Magnetism & Matters | Class 12 Physics Notes, Paramagnetic Substances – Magnetism & Matters | Class 12 Physics Notes, Forces || Newton Laws Of motion || Class 11 Physics Notes. 2015 – Very Short Answer Type Questions [1 Mark] 1. Save my name, email, and website in this browser for the next time I comment. 16:13. For spontaneous reaction $\mathrm{E}^{\circ}>0 \mathrm{so}(\mathrm{A})$, For spontaneous reaction $\mathrm{E}^{\circ}>0 \mathrm{so}(\mathrm{A})$. Vivek SK. (4) $\mathrm{Cl}^{-}$ Plus Two Chemistry Chapter Wise Previous Questions Chapter 3 Electrochemistry is part of Kerala Plus Two Chemistry Chapter Wise Previous Year Questions and Answers. Electrochemistry refers to the branch of chemistry which deals with the flow of electricity and the chemistry behind it. In a hydrogen-oxygen fuel cell, the combustion of hydrogen occurs because of the difference in potential between two electrodes. (1) SHOW SOLUTION The correct relationship between $\lambda_{\mathrm{C}}$ and $\lambda_{\infty}$ is given as: Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. AIEEE 2010 15 ratings • 1 review. It includes questions asked in previous year exams, questions provided by Kendriya Vidyalaya KV schools, DoE, Delhi government school, Navodaya Vidyalaya samiti NVS and other government and private schools in India and abroad that are affiliated to CBSE, New Delhi. (1) $6250 \mathrm{Sm}^{2} \mathrm{mol}^{-1}$ (3), (1) $\mathrm{Cl}^{-}$ and $\mathrm{Br}^{-}$, (2) $\mathrm{Cl}^{-}, \mathrm{Br}^{-}$ and $\mathrm{I}^{-}$, (3) $\mathrm{Br}^{-}$ and $\mathrm{I}^{-}$, Q. (2) $6.25 \times 10^{-4} \mathrm{S} \mathrm{m}^{2} \mathrm{mol}^{-1}$ Chemistry Questions with solution, you have any book for this pl confirm & cost of book, Plz bro questions are dope but i need clr solutions even i cant solve it, Need some more questions plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz, Download India's Leading JEE | NEET | Class 9,10 Exam preparation app, Electrochemistry – JEE Main Previous Year Questions with Solutions. The cell that converts the chemical energy liberatedas a result of redox reaction to electrical energy is called a Daniel cell. Previous Year & Mock Questions. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. A solution of Ni(NO3 )2 is electrolysed between platinum electrodes using 0.1 Faraday electricity. The mass of copper deposited at the cathode is : Students can easily download these solutions in PDF format for free. (1) $\mathrm{p}\left(\mathrm{H}_{2}\right)=2 \operatorname{atm}\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}$ AIEEE 2009 This is the currently selected item. English. Hence option (c) is the answer. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Q. (2) Q. Fact. SHOW SOLUTION Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. For students of class 12 who are looking to give a good performance for their board exams and also to perform well for competitive exams like JEE and more, it is important that they prepare well with the help of important questions which tend to repeat over the years. JEE-Mains 2014 (4) $62.5 \mathrm{S} \mathrm{m}^{2} \mathrm{mol}^{-1}$ Electrolytic cells are those in which a non-spontaneous reaction is controlled by an external source of electric current. AIEEE 2011/JEE-MAIN 2014 The standard reduction potentials for $\mathrm{Zn}^{2+} / \mathrm{Zn}, \mathrm{Ni}^{2+} / \mathrm{Ni}$ and $\mathrm{Fe}^{2+} / \mathrm{Fe}$ are $-0.76,-0.23$ and – 0.44 V respectively. (1), (1) $\mathrm{p}\left(\mathrm{H}_{2}\right)=2 \operatorname{atm}\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}$, (2) $\mathrm{p}\left(\mathrm{H}_{2}\right)=2$ atm and $\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}$, (3) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}$, (4) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}$, Q. Based on the data given above, strongest oxidising agent will be : Higher the SRP, stronger will be oxidising agent. (3) $\mathrm{p}\left(\mathrm{H}_{2}\right)=1$ atm and $\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}$ The correct option among the following is. Shorthand notation for galvanic/voltaic cells. 2. (4) Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. So 0.1 F will deposit (0.1/2) moles of Ni. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. (4) 6.4 hours 1.Conductivity (unit Siemen’s S) is directly proportional to area of the vessel and the concentration of the solution in it and is inversely proportional to the length of the vessel then the unit of the constant of proportionality is (2002) Two Faraday of electricity is passed through a solution of $\mathrm{CuSO}_{4}$. 4.5. Since $\mathrm{Cr}^{+3}$ is having least reducing potential, so Cr is the best Reducing agent. (4) $\mathrm{MnO}_{4}^{-}$ Download Electrochemistry Previous Year Solved Questions PDF, 1. $\mathrm{E}_{\mathrm{Fe}^{-3} / \mathrm{Fe}}^{\circ}=-0.036 \mathrm{V}, \quad \mathrm{E}_{\mathrm{Fe}^{-2} / \mathrm{Fe}}^{\circ}=-0.439 \mathrm{V}$. As far as the JEE exam is concerned, electrochemistry is an important topic. (1) $\lambda_{\mathrm{C}}=\lambda_{\infty}-(\mathrm{B}) \sqrt{\mathrm{C}}$ And also provide detail solutions, Sir , I want to purchase previous years IIT JEE Chapter wise. Calculate the standard cell potential (in V) of the cell in which the following reaction takes place. JEE-Mains 2017 Also, these important questions are prepared by analyzing the previous years question papers & considering the weightage of each chapter in the syllabus. How many moles of Ni will be deposited at the cathode? The reactions carried out using the process of electrochemistry are energy effective and less polluting. (4) I- only The reaction $\mathrm{X}+\mathrm{Y}^{+2} \rightarrow \mathrm{X}^{2+}+\mathrm{Y}$ will be spontaneous when This test is Rated positive by 87% students preparing for Class 12.This MCQ test is related to Class 12 syllabus, prepared by Class 12 teachers. MHT-CET Previous year questions Chapter-wise Chemistry Electrochemistry MHT-CET PCM PYQs MHT-CET Previous year questions Chapter-wise Chemistry Electrochemistry Time limit: 0 amperes current so that the oxygen released can completely burn 27.66 g of diborane ? Chemistry. Since $\mathrm{Cr}^{+3}$ is having least reducing potential, so Cr is the best Reducing agent. JEE-Mains 2016 EMF of a cell in terms of reduction potential of its left and right electrodes is, Ecell = Reduction potential of the cathode – Reduction potential of the anode, 7. Kerala Plus Two Chemistry Chapter Wise Previous Questions and Answers Chapter 3 Electrochemistry Question 1. (2). 13. The specific conductance of the solution is 1.3 S $\mathrm{m}^{-1}$. 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